7p^2-34p-48=0

Solution for 7p^2-34p-48=0 equation:

7p^2-34p-48=0

a = 7; b = -34; c = -48;
Δ = b2-4ac
Δ = -342-4·7·(-48)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-50}{2*7}=\frac{-16}{14}
=-1+1/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+50}{2*7}=\frac{84}{14}
=6
$